7-1 supplement:Sommerfield expansion Set O(E)is continuously diffrentiated between (-co,+o), (0)=0,and lime afEy≥IfkeT<Er, prove that 1-r(E)0'(e)证=Q(e,)+石k,7Q'(E,) where f(E)=- F-D function E-EE
7-1 supplement: Sommerfield expansion Set Q(E) is continuously diffrentiated between(-,+), Q(0)=0 ,and ,α>0。If kBT << EF, prove that lim 0 ( ) E E e Q E − → = ( ) ( ) ( ) ( ) ( ) 2 2 0 d 6 F B F I f E Q E E Q E k T Q E = + where ( ) 1 exp 1 F B f E E E k T = − + F-D function
Prove: I=Jf(E)0(E)dE f(E) -dfdE -j()r 1.0 0 E E E-Eg exp kgT kgT exp E-EE +1 kgT kgT
Prove: ( ) ( ) 0 I f E Q E Ed = ( ) 0 d d d f Q E E E = − d d f E − 2 exp 1 exp 1 F B B F B E E k T k T E E k T − = − + 1 1 exp 1 exp 1 B F F B B k T E E E E k T k T = − − + − +
We find that (-df7dE)is a even function of (E-E), the value of (-dfdE)is mainly focused nearby the scope of E-EF~kBT,if E-EFl>n kBT,the value of the function is approaching 0 rapidly,similar to the function of δ So,the contribution to the integral is mainly focused in the small scope of E~Er,because Er>>kBT,the lower limit of the integral is replaced by -oo from 0,and the integral value is supposed not to be changed. 1=joae
(-df/dE) is a even function of(E-EF), the value of (-df/dE) is mainly focused nearby the scope of E-EF kBT,if E-EF > n kBT,the value of the function is approaching 0 rapidly, similar to the function of δ So, the contribution to the integral is mainly focused in the small scope of E ~ EF,because EF >> kBT,the lower limit of the integral is replaced by -∞ from 0,and the integral value is supposed not to be changed. ( ) d d d f I Q E E E − = − We find that
perform the Taylor expansion on O(E)nearby E=EE (E)=(E)+E)(E-E)+"(Er)(E-E)'+. =iee,〔}r+jQ(Ee-,〔ur +5Q(,6-R,{)c+ wherej()()
perform the Taylor expansion on Q(E) nearby E=EF ( ) ( ) ( )( ) ( )( ) 1 2 2! Q E Q E Q E E E Q E E E F F F F F = + − + − + ( ) ( )( ) d d d d d d F F F f f I Q E E Q E E E E E E − − = − + − − ( )( ) 2 d 1 d 2 d F F f Q E E E E E − + − − + ( ) ( ) 0 d d d F F f I Q E E Q E E − = − = where
4-eec-¥s〔尝 -eie德可0 4=fQe,E-,() g7可 xdx -i
( )( ) 1 d d d F F f I Q E E E E E − = − − ( ) ( ) ( )( ) d 0 1 1 F B x x x x Q E k T e e − − = = + + F B E E x k T − = 令 ( )( ) 2 2 d 1 d 2 d F F f I Q E E E E E − = − − ( ) ( ) ( )( ) 2 2 d 1 2 1 1 F B x x x x Q E k T e e − − = + + ( ) ( ) ( ) 2 2 2 0 d 1 x B F x x e x k T Q E e − − = +