内蒙古大学化学化工学院：《结构化学基础》课程教学资源（各章习题）第一章 量子力学基础知识（答案）

1080T ( =1016×10-17J 1080T= =1016×10-17J 1080 =1.016×10-17J 1080T n=3n() =1016×10-17J

1080 T = ( )  h m m p 2 2 1 2 2 = =1.016×10-17 J 1080 T = ( )  h m m p 2 2 1 2 2 = =1.016×10-17 J 1080 T = ( )  h m m p 2 2 1 2 2 = =1.016×10-17 J 1080 T = ( )  h m m p 2 2 1 2 2 = =1.016×10-17 J

0m=2n()21060 1080T =1016×10-17J 2m 2 =1016×10-17J

1080 T = ( )  h m m p 2 2 1 2 2 = =1.016×10-17 J 1080 T = ( )  h m m p 2 2 1 2 2 = =1.016×10-17 J 1080 T = ( )  h m m p 2 2 1 2 2 = =1.016×10-17 J

10807=2m-2m =1016×1017J 00n=n()-06×0 1080 2m 2m =1016×10-17J

1080 T = ( )  h m m p 2 2 1 2 2 = =1.016×10-17 J 1080 T = ( )  h m m p 2 2 1 2 2 = =1.016×10-17 J 1080 T = ( )  h m m p 2 2 1 2 2 = =1.016×10-17 J

1080 2m2m =1.016×1017J 1080T n=3n() =1016×10-17J

1080 T = ( )  h m m p 2 2 1 2 2 = =1.016×10-17 J 1080 T = ( )  h m m p 2 2 1 2 2 = =1.016×10-17 J

1080T= =1016×10-17J 1080T 2 016×1017J

1080 T = ( )  h m m p 2 2 1 2 2 = =1.016×10-17 J 1080 T = ( )  h m m p 2 2 1 2 2 = =1.016×10-17 J