3丌 L=米=( aa2 + ka 4G oL sa 32 G hEia-l= 323m aas+ ka--a 2G 3丌 G 3 4G (-a2-ka+a3)=-2( sca G )(a) B(ka-3 4G H G 3TC 3Ta 4G 2021/2/5 Zhang De-Hai
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H G bra 3(ka 4G da H G d2 3(ka a2 T 0= (k 3Ta da2 4G 3Ta da2 4G a2y 9r2 a24(21:A a4)y=0 There is a tunneling for k= 1 2021/2/5 Zhang De-Hai
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a-y 9t=(ka2 aa2 4G 3ay=0 p 2m+v, [x, pl=i, p=-iar dy 2m dr2+vy= Ey 2021/2/5 Zhang De-Hai
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ambda越小势越高 C=0 020.生 1.z1.4 2021/2/5 仅闭宇宙才能隧穿!9
2021/2/5 Zhang De-Hai 9 a0 U a a = 0 仅闭宇宙才能隧穿！ Lambda越小势越高
ds2= do2+sin(o)dy v)·d32 this is a four sphere, instanton, simplest 丌/2+i ds2=-dT2+ cosh (T)(d2+ sin2 (v) d2) this is a closed inflating universe a2.k a233 do a=ao cosh(aon), for k=l k=K2=A=1 2021/2/5 a=do sin(ao o), for k=1
2021/2/5 Zhang De-Hai 10 this is a four sphere, instanton, simplest. this is a closed inflating universe