水力学习题答案 1绪论 1.1p=1.359×10kg/m=13590kg/m,Y=133.2kPa=1.332×10kN/m 1.2v=1.003×10m/s 1.3dp=2.18X107N/m 1.4F=184N 1.5u=3.79m/s 1.7μ=0.0721~0.07318Ns/m或Pa.s(按内简半径计算) 2水静力学 2.1p=38.024kN/m2,h=3.88m 2.2取石油与甘油交米面为等压面，压力表读数为G(相对压强)，则有 Pe+(7-3)=29-3) P6=12.56×6-8.17×4=40.82KW/m2 2.3Pa-P4=53.68Pa 2.3煤气密度pm=1.3kg/m3,(第二版) 2.5液面相对压强：22.932kPa,绝对压强：120.932kPe 2.6A点相对压强：p=97.784kPa:(h:=0.lm,h,=0.5m) 2.7Pe=106.1kN/m2,h-0.827m 2.8h,=6m,h2=0.456m 2.9D=18cm 2.10pv=5.88kPa 2.11(1)w=18.67rad/s,(2)w=20.87rad/s,V=0.00353m 2.15h=0.6874m 2.16当下游无水，T=157.73kN:当下游有水，T=80.26kN 217门销度e3m 2.18P=630.98kN,压力体面积：9.198m2,P=857.5kN,P=1064.6kN,a=36.35
2.14 2.24P-98kN,静水总压力作用线过圆心 ic)
(b 777D777 220 (a)
77 (c) 3水动力学基础 3.1=0.5umm 3.2(1)从A断面流向B断面(2)hw-1.79m(3)Q-0.106ms 332=0.64m,2+2=2.64m 3.40-12.130m3/s 3.5pw=56.589kPa d H+h 3.7 d:V H 3.100=0.0313m13,4=0.965 3.13H=1.5m 3.14R=76.264kN 3.15R=3976KN,R,=3.04KN,R=5.05KN,(0-=0.1mBs) 3.16R=384.01kN,当考虑水头损失时轴向推力会变大 3.17 21+cosa 2.1-cosa 9 2 4液流形态及水头损失
4.1层流 42=25.9308N/m 436。=0.095cm 4.4t0=14.7N/m2 4.7=0.04 4.81=0.038h,=0.033m 4.9计算法：1=0.0223，hf=6.64×10-3m 4.103=00.317 4.11n=0.025 412,=3.91m 5有压管道中的恒定流 5.10=0.027m31s。 5.2Q=6.25m/s 5.3Q=0.678m/s 5.4Q-=0.0269m/s△z=0.709m 5.5水泵扬程=29.986m 5.60=0.471m/s,h=526m,(=0.012,飞a-2.5,503，m=1.0) 5.8A点压强水头：21.172m 6明渠恒定均匀流 6.1Q=17.683m/s,0.803ms 6.2v=1.32m1s,Q=6.65m3/s 6.3Q=241.1m/s 6.4Q=20.28m3/s 6.5h=1.lm.b=0.66m