求下列函数的对偶式和反函数 1.F1=(B+A+C+D)(4+B+CD) 2.F,=A+B+CD+AD·B·C 1)F1=B·ACD+AB·C+D F= BAC+abc+D 2)F2=AB(C+D)(A+D+B+C) F2=AB(C+D)(A+D+B+C)
求下列函数的对偶式和反函数： F A B CD AD B C F B A C D A B CD = + + + = + + + + + 2 1 2. 1. ( )( ) F BACD ABC D F B ACD AB C D = + + = + + 1 ' 1 1) ( )( ) 2) ( )( ) 2 ' 2 F AB C D A D B C F AB C D A D B C = + + + + = + + + +
用卡诺图化简 1F1(A,B,C,D)=∑m(,28,10,11 2F2(A,B,C,D)=∑m(0,2,3,5,7,8,9)+∑l(10,1.1,14,15) 3F3(4,B,C,D)=∑m(0,26,8)+∑(9,15) 4F(4,B,C,D)=∑m(0,5,1415)+∑(3,4,13) CD CD 000l1l10 00011110 aB AB 00 01 01 10 F=ABC+acd+ACD+ABc F,=A+BD+C+BD f,=ACD+BCD F=AC +ABC
= + = + = + = 4. ( , , , ) (0,1,5,14,15) (3,4,13) 3. ( , , , ) (0,2,6,8) (9,15) 2. ( , , , ) (0,2,3,5,6,7,8,9) (10,11,12,13,14,15) 1. ( , , , ) (0,1,2,6,8,10,11,12) 4 3 2 1 F A B C D m d F A B C D m d F A B C D m d F A B C D m 用卡诺图化简： 1 1 1 10 1 11 1 01 1 1 1 00 00 01 11 10 AB CD 1 1 x x 10 x x x x 11 1 1 1 01 1 1 1 00 00 01 11 10 AB CD F1 = ABC + ACD + ACD + ABC F2 = A+ BD+C + BD F AC ABC F ACD BCD = + = + 4 3