InP Const.S/ 4 2 H Example9.1 Solution9.1 (a)for Carnotrefeigerator 0+459.67 07n元=80+459.671-0+459675.75
Example 9.1 Solution 9.1 (a) for Carnot refeigerator - C H C T T T = 0 459.67 5.75 (80 459.67) - (0 459.67) + = = + + S T 4 1 2 3 3′ lnP H 2 3 4 1 Const. S
condenser 4 Throttle8 valve compressor 1 t 2 evaporator 换算273*9/5-32 (b)for the vapor-compression cycle H3-H2 H1 H2 H3? T2 saturated vapor S. T4 saturated liquid 用→W=-H,→ 亿→3'))isentropy S=S, W=W/n→H=-用+H2 (4→1)isenthalpy,=H Refrigeration capacity(制冷能力) Qe h
换算 273*9/5-32 （b） for the vapor-compression cycle 2 1 3 2 H H H H − = − H1 H2 H3? T2 saturated vapor H S2 2 T4 saturated liquid H P P 4 4 3 = H3 W H H SR 3 2 = − (2 → 3 ′ ) isentropy 3 2 S S = / W W s SR = H W H 3 2 = − + s (4 → 1) isenthalpy H H 1 4 = Refrigeration capacity （制冷能力） / Q kJ h C 2 1 QC m H H = − condenser 4 1 2 3 compressor Throttle valve evaporator